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Leetcode 236 - Lowest Common Ancestor - change the code between line 96 - line 104, what actually are in the loop, explicitly loop on them.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace LowestCommonAncestors
{
public class TreeNode
{
public TreeNode left;
public TreeNode right;
public int val;
public TreeNode(int v)
{
val = v;
}
}
/*
* May 21, 2016
* Julia's warmup on this algorithm - C# version
* Tips to share:
* 1. Stack, always check stack is not empty before calling peek
* 2. Peek method is good, you can retrieve the information then decide to Pop or not
* 3. Try to make the design simple!
* 4. Stack.Array method keeps the order of iterator
*/
class Program
{
static void Main(string[] args)
{
TreeNode node1 = new TreeNode(9);
node1.left = new TreeNode(5);
node1.right = new TreeNode(8);
node1.left.left = new TreeNode(1);
node1.left.right = new TreeNode(4);
node1.left.right.left = new TreeNode(2);
node1.left.right.right = new TreeNode(3);
node1.right.right = new TreeNode(8);
node1.right.right.left = new TreeNode(6);
TreeNode node = lowestCommonAncestor(node1, node1.left, node1.left.right.left);
}
public static TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q)
{
Stack<TreeNode> stack = new Stack<TreeNode>();
TreeNode runner = root;
List<TreeNode> pPath = new List<TreeNode>();
List<TreeNode> qPath = new List<TreeNode>();
while (true)
{
while (runner != null)
{
stack.Push(runner);
if (runner == p && pPath.Count == 0)
{
pPath.AddRange(stack);
}
if (runner == q && qPath.Count == 0)
{
qPath.AddRange(stack);
}
if (pPath.Count > 0 && qPath.Count > 0)
{
break; // terminate the traversal when both paths have been found
}
runner = runner.left;
}
while (stack.Count > 0 && (stack.Peek().right == null || stack.Peek().right == runner))
{
runner = stack.Pop();
}
if (stack.Count == 0)
{
break;
}
else
{
runner = stack.Peek().right;
}
}
int pIndex = pPath.Count - 1;
int qIndex = qPath.Count - 1;
while (pIndex >= 0 && qIndex >= 0 && pPath[pIndex] == qPath[qIndex])
{
pIndex--;
qIndex--;
}
return pPath[pIndex + 1];
}
}
}
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