Skip to content

Instantly share code, notes, and snippets.

@jianminchen
Created January 21, 2018 06:57
Show Gist options
  • Star 0 You must be signed in to star a gist
  • Fork 0 You must be signed in to fork a gist
  • Save jianminchen/3eb8126b68ec074846ef8b514a584db8 to your computer and use it in GitHub Desktop.
Save jianminchen/3eb8126b68ec074846ef8b514a584db8 to your computer and use it in GitHub Desktop.
Catalan number - January 20 10:00 PM mock interview - peer asked me how to make an array copy - check reference copy, it does not work. And then use it array.Copy
using System;
class Solution
{
public static int NumOfPathsToDest(int n)
{
if( n == 0)
{
return 0;
}
var currentRow = new int[n];
var previousRow = new int[n];
for(int row = 0; row < n; row++) // row = 1
{
var firstRow = row == 0;
for(int col = 0; col < n; col++)
{
if(firstRow)
{
currentRow[col] = 1;
}
else
{
currentRow[col] = 0;
if(row <= col) // underneath diagnal line
{
currentRow[col] = currentRow[col - 1] + previousRow[col];
}
}
}
// set previous = current
/*
for(int col = 0; col < n; col++)
{
previousRow[col] = currentRow[col];
}
*/
Array.Copy(currentRow, previousRow, n);
}
return currentRow[n - 1];
}
static void Main(string[] args)
{
}
}
/*
Constaints:
(0,0) only can go east(right) or go up (north), you cannnot cross the diagnol line
start from (0,0)
Try to solve path(n-1, n-1)
x x x x 14 Dest(5 -1 , 5 -1)
x x x 5 14
x x 2 5 9
x 1 2 3 4
1 1 1 1 1
________________
0 1 2 3
(0,0)
A[row,j] = 1; row = 0
A[row, col] = A[row, col -1] + A[row - 1, col] row > 0, row < col
time complexity O(n * n)
n * n -> keep two rows -> current row / previous row -> space O(n)
*/
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment