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January 20, 2018 07:04
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Sudoku solver - mock interview 30 minutes - January 19, 2018
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using System; | |
using System.Collections.Generic; | |
class Solution | |
{ | |
const int LastColumn = 8; | |
public static bool SudokuSolve(char[,] board) // 9 * 8 | |
{ | |
if(board == null || board.GetLength(0) != 9 || board.GetLength(1) != 9) // false | |
{ | |
return false; | |
} | |
return sudokuSolveHelper(board, 0, 0); | |
} | |
private static bool sudokuSolveHelper(char[,] board, int startRow, int startCol) | |
{ | |
// base case | |
if(startRow == 9) | |
{ | |
return true; | |
} | |
var current = board[startRow, startCol]; // '5' | |
var isDot = current == '.'; // false | |
var nextRow = startCol == LastColumn? (startRow + 1) : startRow; // 0 | |
var nextColumn = startCol == LastColumn? 0 : (startCol + 1); // 1, 2 | |
if(!isDot) | |
{ | |
return sudokuSolveHelper(board, nextRow, nextColumn); // 0, 1 | |
} | |
else | |
{ | |
var set = getAvailableChars(board, startRow, startCol); // | |
foreach(var number in set) | |
{ | |
board[startRow, startCol] = number; | |
if(sudokuSolveHelper(board, nextRow, nextColumn)) | |
{ | |
return true; | |
} | |
board[startRow, startCol] = '.'; | |
} | |
return false; | |
} | |
} | |
private static HashSet<char> getAvailableChars(char[,] board, int startRow, int startCol) | |
{ | |
var avaiable = new HashSet<char>("123456789".ToCharArray()); | |
//check row | |
for(int col = 0; col < 9; col++) | |
{ | |
avaiable.Remove(board[startRow, col]); | |
} | |
//check column | |
for(int row = 0; row < 9; row++) | |
{ | |
avaiable.Remove(board[row, startCol]); | |
} | |
//check 3*3 matrix | |
int smallMatrixRow = startRow/ 3 * 3; // 0, 3, 6 | |
int smallMatrixCol = startCol/ 3 * 3; | |
for(int row = smallMatrixRow; row < smallMatrixRow + 3; row++) | |
{ | |
for(int col = smallMatrixCol; col < smallMatrixCol + 3; col++) | |
{ | |
avaiable.Remove(board[row, col]); | |
} | |
} | |
return avaiable; | |
} | |
static void Main(string[] args) | |
{ | |
} | |
} | |
/* | |
9 * 9 10 option '1', '2', ...'9', '.' | |
Constraint: each row there is no duplicated char, each column there is no duplicated char, | |
3 * 3 you can not repeat | |
DFS + backtracking | |
(0, 0) '5' ->(0, 1 ) :'3'-> '.', 3, 5, 6, 7, 8, 9 -> try set: {1, 2, 4} | |
'1' -> true- > return true, subproblem | |
Time complexity | |
9^81 -> backtracking | |
Space complexity | |
*/ |
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