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April 3, 2020 17:13
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Search in rotated sorted array - March 31, 2020 - 10:00 PM mock interview as an interviewer, interviewee wrote bug free code in less than 8 minutes 40 seconds
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import java.io.*; | |
import java.util.*; | |
/* | |
* To execute Java, please define "static void main" on a class | |
* named Solution. | |
* | |
* If you need more classes, simply define them inline. | |
*/ | |
class Solution { | |
public int findValueInRotatedArray(int[] nums, int target) { | |
if(nums == null || nums.length == 0) { | |
return -1; | |
} | |
int lo = 0; | |
int hi = nums.length - 1; | |
while(lo <= hi) { | |
int mid = lo + (hi - lo) / 2; | |
if(nums[mid] == target) { | |
return mid; | |
} | |
// If left side is sorted. | |
if(nums[lo] <= nums[mid]) { | |
if(target >= nums[lo] && target <= nums[mid]) { | |
hi = mid - 1; | |
} | |
else { | |
lo = mid + 1; | |
} | |
} else { | |
if(target > nums[mid] && target <= nums[hi]) { | |
lo = mid + 1; | |
} else { | |
hi = mid - 1; | |
} | |
} | |
} | |
return -1; | |
} | |
public static void main(String[] args) { | |
Solution solver = new Solution(); | |
int[] nums = new int[]{7, 9, 11, 1, 2, 5}; | |
int[] nums1 = new int[]{1, 2, 5, 7, 9, 11}; | |
System.out.println(solver.findValueInRotatedArray(nums, 2) == 4); | |
System.out.println(solver.findValueInRotatedArray(nums, 8) == -1); | |
System.out.println(solver.findValueInRotatedArray(nums1, 1) == 0); | |
System.out.println(solver.findValueInRotatedArray(nums1, 11) == 5); | |
System.out.println(solver.findValueInRotatedArray(nums1, 12) == -1); | |
} | |
} | |
/* | |
given an integer sorted array, rotated in unknown position, given a value, find index position of the array. If not found, return -1. | |
[1, 3, 5, 7, 9, 11] | |
rotated | |
[7, 9, 11, 1, 2, 5], given a value 2, return 4; | |
given a value 8, return -1 | |
bool findValueInRotate(int[] numbers, int target) | |
*/ |
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