Created
March 27, 2016 16:00
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HackerRank - String - Sherlocks and Anagrams - more than 2 hours work
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using System; | |
using System.Collections; | |
using System.Collections.Generic; | |
using System.Linq; | |
using System.Text; | |
using System.Threading.Tasks; | |
namespace SherlockAndAnagrams | |
{ | |
class Program | |
{ | |
static void Main(string[] args) | |
{ | |
int n = Convert.ToInt16(Console.ReadLine()); | |
for(int i = 0; i< n; i++) | |
{ | |
Console.WriteLine(anagrammaticPair(Console.ReadLine().Trim())); | |
} | |
} | |
public static int anagrammaticPair(string s) | |
{ | |
if (s == null || s.Length == 0) return 0; | |
int n = s.Length; | |
int count = 0; | |
for(int i=1; i<= n-1; i++) | |
{ | |
count += aPair(s, i); | |
} | |
return count; | |
} | |
/* | |
* get the anagrammatic pair of length m | |
* | |
* substring S[i,j] with length m, at most n - m, n is length of string | |
*/ | |
private static int aPair(string s, int m) | |
{ | |
Hashtable table = getTable( s, m); | |
int count = 0; | |
foreach(string s1 in table.Keys) | |
{ | |
IList<int> list = (IList<int>)table[s1]; | |
count += getPairs(list, m); | |
} | |
return count; | |
} | |
private static int getPairs(IList<int> list, int m) | |
{ | |
int n = list.Count; | |
return n*(n-1)/2; | |
} | |
private static Hashtable getTable(string s, int m) | |
{ | |
Hashtable table = new Hashtable(); | |
int n = s.Length; | |
for (int i = 0; i <= n - m; i++) | |
{ | |
string tmp = s.Substring(i, m); | |
//if (table.Contains(tmp)) | |
string key = ""; | |
if(tableContainsAnagram(table, tmp, ref key)) | |
{ | |
IList<int> list = (IList<int>)table[key]; | |
IList<int> newList = new List<int>(list); | |
newList.Add(i); | |
table[key] = newList; | |
} | |
else | |
{ | |
IList<int> list = new List<int>(); | |
list.Add(i); | |
table.Add(tmp, list); | |
} | |
} | |
return table; | |
} | |
private static bool tableContainsAnagram(Hashtable table, string tmp, ref string key) | |
{ | |
foreach(string s in table.Keys) | |
{ | |
if (isAnagram(s, tmp)) | |
{ | |
key = s; | |
return true; | |
} | |
} | |
return false; | |
} | |
/* | |
* Two strings are anagram, count of char should be same | |
*/ | |
private static bool isAnagram(string s1, string s2) | |
{ | |
int[] cA = new int[26]; | |
foreach(char c in s1) | |
{ | |
cA[c - 'a'] ++; | |
} | |
foreach (char c in s2) | |
{ | |
cA[c - 'a'] --; | |
} | |
foreach (int val in cA) | |
{ | |
if (val != 0 ) | |
return false; | |
} | |
return true; | |
} | |
} | |
} |
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