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August 29, 2015 14:02
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convert in-order and pre-order tree presentation to post-order
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#test cases | |
in_order_1 = "ABCDEFG" | |
pre_order_1 = "DBACEGF" | |
post_order_1 = "ACBFGED" | |
in_order_2 = "CBAD" | |
pre_order_2 = "BCAD" | |
post_order_2 = "CDAB" | |
def convert(in_order, pre_order): | |
#get root node | |
root = pre_order[0] | |
#find corresponding in-order representation for left and right subtree | |
in_left = in_order[:in_order.find(root)] | |
in_right = in_order[in_order.find(root) + 1:] | |
#recursively invoke | |
left = convert(in_left, pre_order[1:len(in_left) + 1]) if in_left else "" | |
right = convert(in_right, pre_order[len(in_left) + 1:]) if in_right else "" | |
#return post order | |
return left + right + root | |
assert convert(in_order_1, pre_order_1) == post_order_1 | |
assert convert(in_order_2, pre_order_2) == post_order_2 | |
assert convert("ADEFGHMZ", "GDAFEMHZ") == "AEFDHZMG" | |
print "OK" |
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