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@jmelloy
Created June 28, 2013 21:47
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select pdbcode, pdbchain, cnt, other_col
from pdbcode a,
(select pdbcode, count(*) cnt
from pdbcode
group by pdbcode) b
where a.pdbcode = b.pdbcode
@lennax
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lennax commented Jun 28, 2013

SELECT pdbcode, pdbchain, n_chain, uniprotkbac, mc_skip, pisces FROM pdb
JOIN (SELECT pdbcode, count(pdbchain) AS n_chain FROM pdb GROUP BY pdbcode)
USING (pdbcode);

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