Created
October 19, 2022 06:29
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Compute all permutations of a list
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///usr/bin/env jbang "$0" "$@" ; exit $? | |
//DEPS org.junit.jupiter:junit-jupiter-api:5.7.2 | |
//DEPS org.assertj:assertj-core:3.11.1 | |
//JAVA 17 | |
import static org.assertj.core.api.Assertions.assertThat; | |
import java.util.ArrayList; | |
import java.util.Arrays; | |
import java.util.List; | |
import java.util.Optional; | |
import java.util.stream.Collectors; | |
import org.junit.jupiter.api.Test; | |
public class ListPermutations { | |
private static <T> List<List<T>> computePermutations(List<T> list) { | |
return addOneRemaining(List.of(), list); | |
} | |
private static <T> List<List<T>> addOneRemaining(List<List<T>> list, List<T> remaining) { | |
if (remaining.isEmpty()) { | |
return list; | |
} | |
List<List<T>> r = new ArrayList<>(); | |
for (T e : remaining) { | |
List<T> newRemaining = remaining.stream() | |
.filter(i -> i != e) | |
.toList(); | |
List<List<T>> newList; | |
if (list.isEmpty()) { | |
newList = List.of(List.of(e)); | |
} else { | |
newList = list.stream() | |
.map(l -> { | |
List<T> n = new ArrayList<>(); | |
n.addAll(l); | |
n.add(e); | |
return n; | |
}) | |
.toList(); | |
} | |
r.addAll(addOneRemaining(newList, newRemaining)); | |
} | |
return r; | |
} | |
public static void main(String[] args) { | |
List<String> list = Arrays.asList(args); | |
System.out.println("input list:"); | |
System.out.println(listAsString(list)); | |
System.out.println("all permutations:"); | |
List<List<String>> all = computePermutations(list); | |
System.out.println(allAsString(all)); | |
} | |
private static String listAsString(List<String> list) { | |
return list.stream() | |
.collect(Collectors.joining(", ", "[", "]")); | |
} | |
private static String allAsString(List<List<String>> all) { | |
return all.stream() | |
.map(ListPermutations::listAsString) | |
.collect(Collectors.joining("\n ", "[\n ", "\n]")); | |
} | |
@Test | |
void testAB() throws Exception { | |
List<String> list = List.of("a", "b"); | |
List<List<String>> result = computePermutations(list); | |
System.out.println(allAsString(result)); | |
assertThat(result).hasSize(2) | |
.anySatisfy(l -> assertThat(l).containsExactly("a", "b")) | |
.anySatisfy(l -> assertThat(l).containsExactly("b", "a")); | |
} | |
@Test | |
void testABC() throws Exception { | |
List<String> list = List.of("a", "b", "c"); | |
runTest(list, 6); | |
} | |
@Test | |
void testABCD() throws Exception { | |
List<String> list = List.of("a", "b", "c", "d"); | |
runTest(list, 24); | |
} | |
@Test | |
void testABCDE() throws Exception { | |
List<String> list = List.of("a", "b", "c", "d", "e"); | |
runTest(list, 120); | |
} | |
private void runTest(List<String> list, int expected) { | |
List<List<String>> result = computePermutations(list); | |
System.out.println(allAsString(result)); | |
assertThat(result).hasSize(expected) | |
.allSatisfy(l -> assertThat(l).containsExactlyInAnyOrderElementsOf(list)); | |
assertThat(result.stream() | |
.distinct() | |
.count()).isEqualTo(expected); | |
} | |
} |
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Run it with jbang:
Produces the output: