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River crossing puzzle
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import itertools as it | |
NTHUGS = 3 | |
NCASES = 2 | |
BOATCAP = 3 | |
thugs = set() | |
cases = set() | |
owner = dict() | |
nresults = 0 | |
for i in range(NTHUGS): | |
t = "thug"+str(i) | |
thugs.add(t) | |
for j in range(NCASES): | |
c = "case"+str(i)+str(j) | |
cases.add(c) | |
owner[c] = t | |
def is_valid(config): | |
cs = cases & config | |
ts = thugs & config | |
if not ts: | |
return True | |
else: | |
for c in cs: | |
if owner[c] not in ts: | |
return False | |
return True | |
def is_end(config): | |
return len(config) == NTHUGS*(1 + NCASES) | |
def print_result(steps): | |
global nresults | |
nresults +=1 | |
print("\nResult {}".format(nresults)) | |
print("----------------") | |
for s in steps: | |
print(s) | |
def solve_further(configs_seen,steps,boat_side,off_side,where): | |
if where=="right" and is_end(boat_side): | |
print_result(steps) | |
return | |
nxt = "left" if where=="right" else "right" | |
for n in range(1,BOATCAP+1): | |
for p in it.combinations(boat_side,n): | |
passengers = set(p) | |
# Must have at least one thug in the boat | |
if not (passengers & thugs): | |
continue | |
off_side2 = boat_side - passengers | |
boat_side2 = off_side | passengers | |
if not (is_valid(boat_side2) and is_valid(off_side2)): | |
continue | |
nconfig = (boat_side2,off_side2) | |
# Do not repeat configurations | |
if nconfig in configs_seen: | |
continue | |
solve_further(configs_seen+[nconfig],steps+[passengers], | |
boat_side2,off_side2,nxt) | |
start = thugs|cases | |
solve_further([],[],start,set(),"left") |
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