Setting, deleting and retrieving cookies in Typescript.

cookie-typescript-utils.ts

/*
 * General utils for managing cookies in Typescript.
 */
export function setCookie(name: string, val: string) {
    const date = new Date();
    const value = val;

    // Set it expire in 7 days
    date.setTime(date.getTime() + (7 * 24 * 60 * 60 * 1000));

    // Set it
    document.cookie = name+"="+value+"; expires="+date.toUTCString()+"; path=/";
}

export function getCookie(name: string) {
    const value = "; " + document.cookie;
    const parts = value.split("; " + name + "=");
    
    if (parts.length == 2) {
        return parts.pop().split(";").shift();
    }
}

export function deleteCookie(name: string) {
    const date = new Date();

    // Set it expire in -1 days
    date.setTime(date.getTime() + (-1 * 24 * 60 * 60 * 1000));

    // Set it
    document.cookie = name+"=; expires="+date.toUTCString()+"; path=/";
}

The error Object is possibly 'undefined' appears to be from typescript thinking .pop() can return an undefined result (even though the length check should prevent that).

For me it goes away with:

if (parts.length === 2) {
	const ppop = parts.pop();
	if (ppop) {
		return ppop.split(";").shift();
	}
}

You are missing the return type for getCookie.

Just commenting to say that with the latest typescript you could solve the pop undefined scenario like this

export function getCookie(name: string) {
    const value = "; " + document.cookie;
    const parts = value.split("; " + name + "=");
    
    if (parts.length == 2) {
        return parts.pop()?.split(";").shift();
    }
}

Alternatively if you'd like to consistently return a string you could do it like this

  return (
    (parts.length === 2 &&
      parts
        .pop()
        ?.split(";")
        .shift()) ||
    ""
  );

thank you krub

Thank you. This has helped me weening myself from jQuery Libraries...and morphing my js to ts.