10 day JS challenge - Day 3: Alternating Sums

AlternatingSums.js

const alternatingSums = weights => [
    weights.filter((weight, i) => i % 2 === 0).reduce((a, c) => a + c),
    weights.filter((weight, i) => i % 2 !== 0).reduce((a, c) => a + c)
];


describe('alternatingSums()', () => {
    it('returns alternating sums of even and odd', () => {
        // arrange
        const nums = [50, 60, 60, 45, 70];
        
        // act
        const result = alternatingSums(nums);

        // log
        console.log("result: ", result);
        
        // assert
        expect(result).toEqual([180, 105]);
    });
});