Created
September 9, 2012 23:19
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/* Fully recursive */ | |
public int pow(int b, int e) { | |
if(b == 0) return 1; | |
if(e%2 == 0) return pow(b*b, e/2); | |
return b*pow(b, e-1); | |
} | |
/* tail recursive */ | |
public int pow(int b, int e) { return _pow(b,e,1); } | |
public int _pow(int b, int e, int ans) { | |
if(b==0) return ans; | |
if(e%2==0) return _pow(b*b, e/2, ans); | |
return _pow(b, e-1, ans*b); | |
} | |
/* unroll tail recursion */ | |
public int pow(int b, int e) { | |
int ans = 1; | |
while(e > 0) { | |
if(e%2==1) { | |
ans *= b; | |
e--; | |
} | |
else { | |
b*=b; | |
e/=2; | |
} | |
} | |
return ans; | |
} | |
/* After the odd case, we'll always be even next time. | |
* We also see that "e--" was unnecessary. | |
* This is now the "canonical" imperative solution. | |
*/ | |
public int pow(int b, int e) { | |
int ans = 1; | |
while(e > 0) { | |
if(e%2==1) { | |
ans *= b; | |
} | |
b*=b; | |
e/=2; | |
} | |
return ans; | |
} |
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