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4.1 Sum of a Range (Eloquent JavaScript Solutions)
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// step parameter is optional | |
// if step is not passed in, | |
// and start is less than or equal to end, | |
// then step = 1, else step = -1 | |
function range(start, end, step = start <= end ? 1 : -1) { | |
let result = []; | |
// loop iterates up for positive step values | |
// and iterates down for negative step values | |
for (let i = start; step >= 0 ? i <= end : i >= end; i+=step) { | |
result.push(i); | |
} | |
return result; | |
} | |
function sum(numbers) { | |
result = 0; | |
for (let num of numbers) { | |
result += num; | |
} | |
return result; | |
} | |
console.log(range(1, 10)); | |
// → [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] | |
console.log(range(1, 10, 2)); | |
// → [1, 3, 5, 7, 9] | |
console.log(range(5, 2, -1)); | |
// → [5, 4, 3, 2] | |
console.log(range(5, 2)); | |
// → [5, 4, 3, 2] | |
console.log(range(10, 1, -3)); | |
// → [10, 7, 4, 1] | |
console.log(sum(range(1, 10))); | |
// → 55 | |
console.log(sum(range(1, 10, 2))); | |
// → 25 | |
console.log(sum(range(10, 1, -3))); | |
// → 22 (10 + 7 + 4 + 1) |
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Thank you so so so much indeed really helpful
especially with explain.