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Find the smallest set of non-negative integers such that all non-negative integers up to n can be represented as a sum of two elements; see https://math.stackexchange.com/questions/2835313.
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public class Question2835313 { | |
public static void main (String [] args) { | |
int min = 1; | |
int binom = 1; | |
int [] set = {}; | |
int l = 2; | |
for (int n = 2;n <= 100;n++) { | |
if (binom <= n) { | |
min++; | |
binom = (min * (min + 1)) / 2; | |
if (binom <= n) | |
throw new InternalError (); | |
} | |
int s = (int) Math.sqrt (n + 4); | |
int r = n + 4 - s * s; | |
int delta = s & 1; | |
int max = ((int) Math.ceil ((r + delta) / (double) (s + delta)) + 2 * s - 3); | |
if (!generates (set,n)) { | |
for (l = Math.max (l,min);l <= max;l++) { | |
set = new int [l]; | |
int [] coveringCounts = new int [n + 1]; | |
coveringCounts [0] = 1; | |
coveringCounts [1] = 2; | |
coveringCounts [2] = 1; | |
set [1] = 1; | |
if (recurse (set,coveringCounts,3,2,l,n,n / 2 + 2)) | |
break; | |
long start = System.currentTimeMillis (); | |
try { | |
System.out.println ("trying " + n); | |
if (recurse (set,coveringCounts,3,2,l,n,n)) | |
break; | |
} | |
finally { | |
long stop = System.currentTimeMillis (); | |
System.out.println ("time: " + n + " : " + (stop - start) / 1000); | |
} | |
} | |
} | |
System.out.print (n + "&" + min + "&" + max + "&" + set.length + "&\\{"); | |
for (int i : set) { | |
if (i != 0) | |
System.out.print (','); | |
System.out.print (i); | |
} | |
System.out.println ("\\}\\\\"); | |
} | |
} | |
static boolean generates (int [] set,int n) { | |
int nuncovered = n + 1; | |
boolean [] covered = new boolean [nuncovered]; | |
for (int i : set) | |
for (int j : set) { | |
int sum = i + j; | |
if (sum <= n && !covered [sum]) { | |
if (--nuncovered == 0) | |
return true; | |
covered [sum] = true; | |
} | |
} | |
return false; | |
} | |
static boolean recurse (int [] set,int [] coveringCounts,int ncovered,int index,int l,int n,int max) { | |
if (index == l) | |
return ncovered == n + 1; | |
if ((l * (l + 1)) / 2 - (index * (index + 1)) / 2 > n - ncovered) | |
for (set [index] = set [index - 1] + 1;set [index] <= max - l + index + 1;set [index]++) { | |
for (int i = 0;i <= index;i++) { | |
int sum = set [i] + set [index]; | |
if (sum <= n) { | |
if (coveringCounts [sum] == 0) | |
ncovered++; | |
coveringCounts [sum]++; | |
} | |
} | |
if (recurse (set,coveringCounts,ncovered,index + 1,l,n,max)) | |
return true; | |
for (int i = 0;i <= index;i++) { | |
int sum = set [i] + set [index]; | |
if (sum <= n) { | |
coveringCounts [sum]--; | |
if (coveringCounts [sum] == 0) | |
ncovered--; | |
} | |
} | |
} | |
return false; | |
} | |
} |
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