create directory structure

create directory structure in ruby

def dt(path,name=nil)

  if not name
    data = {}
    data[:root] = children = []
  else
    data = {:name => name }
    data[:branches] = children = []
  end
  dirs = [];  files = []
  Dir.foreach(path) do |entry|
    next if (entry == '..' || entry == '.')
    if File.directory?(File.join(path, entry))
      dirs << entry
    else
      files << entry
    end
  end
  dirs.sort.each do |d|
    full_path = File.join(path, d)
    children << dt(full_path, d)
  end
  files.sort.each do |f|
    children << {:name => f}
  end
  return data
end

gistfile1.txt

#!/usr/bin/env coffee

# looking to generate something like:
# {"root":[{"name":"a","branches":[{"name":"aa"},{"name":"bb"}]},{"name":"b"},{"name":"c"}]}

fs = require 'fs'
Path = require 'path'

dir_tree = (path,name=null) ->
  if not name
    data = {}
    data["root"] = children = []
  else
    data = {"name": name }
    data["branches"] = children = []

  dirs = []; files = []
  fs.readdir path,(err,files) =>
    for entry in files
      continue if entry == '..' || entry == '.'
      fs.stat entry,(err,stat) =>
        #### XXX Entry is set to the first element
        console.log entry
        if stat.isDirectory()
          dirs.push(entry)
        else
          files.push(entry)
     for d in dirs  # XXX need to sort
       children.push(dir_tree(Path.join(path,d),d))
     for f in files # XXX need to sort
       children.push {"name": f }
  return data

## XX returns empty: { root: [] }
console.log dir_tree(".")