Created
October 23, 2015 07:16
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Find SQRT with help of Binary Search
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public class FindSqrt { | |
public static int sqrt(int no) { | |
int result = 0; | |
int low = 0, high = (no / 2), mid = 0; | |
int midVal = 0; | |
while (low <= high) { | |
mid = (low + high) / 2; | |
System.out.println("Mid Point :" + mid); | |
midVal = mid * mid; | |
if (midVal == no) { | |
result = mid; | |
break; | |
} else if (midVal > no) { | |
high = mid - 1; | |
} else if (mid < no) { | |
low = mid + 1; | |
} | |
} | |
return result; | |
} | |
public static void main(String[] args) { | |
System.out.println("Final ::" + sqrt(64)); | |
} | |
} | |
/* | |
Output : | |
Mid Point :16 | |
Mid Point :7 | |
Mid Point :11 | |
Mid Point :9 | |
Mid Point :8 | |
Final ::8 | |
*/ |
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