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@jrudolph
Created May 11, 2010 10:13
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trait MapReduce[E, R] {
type S
def map(e: E): S
def reduce(s1: S, s2: S): S
def finish(s: S): R
}
def linear[E, R](seq: Array[E], mr: MapReduce[E, R]): R =
mr.finish(seq.map(mr.map).reduceLeft(mr.reduce))
def divideAndConquer[E, R](seq: Seq[E], mr: MapReduce[E, R]): R = {
def inner(seq: Seq[E]): mr.S =
if (seq.size == 1)
mr.map(seq(0))
else if (seq.size < 5)
seq.map(mr.map).reduceLeft(mr.reduce)
else {
val pivot = seq.size / 2
val (s1, s2) = seq.splitAt(pivot)
mr.reduce(inner(s1), inner(s2))
}
mr.finish(inner(seq))
}
/**
* A parallelizable version of an algorithm to compute the length
* of the longest streak of elements satisfying a certain predicate.
*/
def longestStreakLength[E](pred: E => Boolean): MapReduce[E, Int] =
new MapReduce[E, Int] {
/*
* State is either a tuple of
* (front, max, end) where front/end are the numbers
* of matching elements found at the front/end and max
* is the current maximum. Or it is just the number of elements
* if it is just one long streak.
*/
type S = Either[(Int, Int, Int), Int]
def map(e: E): S = if (pred(e)) Right(1) else Left((0, 0, 0))
def finish(s: S): Int = s match {
case Left((_, max, _)) => max
case Right(max) => max
}
def reduce(s1: S, s2: S): S = (s1, s2) match {
case (Right(x), Right(y)) => Right(x + y)
case (Left((v1, m1, h1)), Right(y)) => Left(v1, Math.max(m1, h1 + y), h1 + y)
case (Right(x), Left((v2, m2, h2))) => Left(x + v2, Math.max(m2, x + v2), h2)
case (Left((v1, m1, h1)), Left((v2, m2, h2))) => Left(v1,Math.max(Math.max(m1, m2), h1 + v2), h2)
}
}
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