Java - Checks if the number is a sum of any of the 2 numbers in the list

Java Contains Sum.java

import java.util.Arrays;

public class App {

    public static void main( String[] args ) {
        int[] inArray = {1, 3, 3, 5, 7};
        int baseNum = 6;

        System.out.println("Number List: " + Arrays.toString(inArray) );
        // Should return true
        // as the sum of the 2nd and 3rd element is 6.
        System.out.println( baseNum + " is a sum of any 2 numbers in the list: " + hasBaseNumberAsSum(inArray, baseNum) );

        baseNum = 14;

        // Should return false.
        // The element should not be added by itself,
        // that's why even if last element is (7 + 7 = 14),
        // it should return false as that adding by itself if invalid.
        System.out.println( baseNum + " is a sum of any 2 numbers in the list: " + hasBaseNumberAsSum(inArray, baseNum) );

        // Should return true
        // As the sum of the 3rd and fourth element is 8
        baseNum = 8;
        System.out.println( baseNum + " is a sum of any 2 numbers in the list: " + hasBaseNumberAsSum(inArray, baseNum) );
    }

    /**
     * Determines if the given baseNum is a sum of any of the numbers in the inArray,
     * excluding the number itself.
     *
     * @param inArray
     * @param baseNum
     * @return
     */
    static boolean hasBaseNumberAsSum(int[] inArray, int baseNum){

        for (int i=0; i < inArray.length; i++){
            for (int j=0; j < inArray.length; j++){

                // skip if the index is the same, so it won't check the sum of itself.
                if ( i == j)
                    continue;
                // check if the sum of the 2 separate numbers is equals the given baseNum
                if ( (inArray[i] + inArray[j] == baseNum))
                    return true;

            }
        }

        return false;
    }

}