Advent of code, dec, 4th 2022, parts 1 and 2

day4.py

"""
( https://adventofcode.com/2022/day/4 )

SPOILER ALERT! The snippets in here present a complete solution


This is both "my style" and what I like most about Python:
creating a minimal class which implements one or more operators
turns the solving of thiz puzzle into a super-readable
one liner!

### attempt that I solve these in an Ipython interactive session.
### (terminal based) - so I just type in the functions/methods/classes that I need,
### and go storing intermediate results in lists or other structures as I see fit.
### (in this case "aa" for each line of the input as a string, and "bb" as created bellow)
"""

# The class:


class Plift:
    def __init__(self, rng):
        self.lower, self.upper = map(int, rng.split("-"))
    def __contains__(self, other):
        return self.lower <= other.lower and self.upper >= other.upper
    def __repr__(self):
        return f"({self.lower}, {self.upper})"

# one line to parse the input into pairs of "Borg" instances:

bb = [tuple(Plift(part) for part in  line.split(",")) for line in aa]

# and one-liner to solve it all:
sum((line[0] in line[1]) or (line[1] in line[0])  for line in bb )

# for part 2, the "counting" criteria changes from finding "included" ranges
# to overlapped ranges. I opted to use the "|" (binary or) operator for that -
# just typed in the new method at the prompt¨:

def __or__(self, other):
    return self.lower <= other.upper and self.upper >= other.lower

# and assigned it to the _Existing_ class:
Plift.__or__ = __or__

# instantly, all instances already
# created of "Plift" in the "bb" list now have the capabiity
# of checking for overlapping with the "|" operator

# And now, one line for totalizing part 2:

sum(line[0] |  line[1]  for line in bb)