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November 3, 2011 19:27
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Removing duplicate triangles with numpy
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import numpy as np | |
def remove_duplicates(array_data, return_index=False, return_inverse=False): | |
"""Removes duplicate rows of a multi-dimensional array. Returns the | |
array with the duplicates removed. If return_index is True, also | |
returns the indices of array_data that result in the unique array. | |
If return_inverse is True, also returns the indices of the unique | |
array that can be used to reconstruct array_data.""" | |
unique_array_data, index_map, inverse_map = np.unique( | |
array_data.view([('', array_data.dtype)] * \ | |
array_data.shape[1]), return_index=True, | |
return_inverse=True) | |
unique_array_data = unique_array_data.view( | |
array_data.dtype).reshape(-1, array_data.shape[1]) | |
# unique returns as int64, so cast back | |
index_map = np.cast['uint32'](index_map) | |
inverse_map = np.cast['uint32'](inverse_map) | |
if return_index and return_inverse: | |
return unique_array_data, index_map, inverse_map | |
elif return_index: | |
return unique_array_data, index_map | |
elif return_inverse: | |
return unique_array_data, inverse_map | |
return unique_array_data | |
vert_indices = np.array([[0,1,2], [2,3,4], [5,6,7], [2,3,4], [1,3,5]]) | |
normal_indices = np.array([[9,8,7], [6,5,4], [3,2,1], [10,11,12], [13,14,15]]) | |
print 'Original indices:' | |
print vert_indices | |
print normal_indices | |
unique_vert_indices, index_map = remove_duplicates(vert_indices, return_index=True) | |
print 'After removing duplicates:' | |
print unique_vert_indices | |
print normal_indices[index_map] |
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Thanks, also very helpful for unique'ing rows in a numpy array...