Python 'Timeout' class that will raise an exception after the containing code does not finish within a specified number of seconds. Use the 'retry' decorator to retry the function a specified number of times after the timeout. NOTE: this works for Unix only. Additionally, signal only works in main thread.

timeout_and_retry_function.py

import time
import signal
from retrying import retry


class Timeout:
    def __init__(self, seconds=1, error_message='Timeout'):
        self.seconds = seconds
        self.error_message = error_message
        
    def handle_timeout(self, signum, frame):
        raise TimeoutError(self.error_message)
        
    def __enter__(self):
        signal.signal(signal.SIGALRM, self.handle_timeout)
        signal.alarm(self.seconds)
        
    def __exit__(self, type, value, traceback):
        signal.alarm(0)


@retry(stop_max_attempt_number=6)  # stop after 6 attempts
def long_running_function():
    with Timeout(seconds=5):
        print("Doing something that takes a while...")
        time.sleep(10)

long_running_function()