fuck overriding == to not return a bool.py

import numpy as np
from itertools import groupby


def fuck_my_face():
    A = np.ones((5, 2)) # A is array([[1, 1], [1, 1], [1, 1], [1, 1], [1, 1]])
    B = np.ones((5, 2)) # B is array([[1, 1], [1, 1], [1, 1], [1, 1], [1, 1]])

    if (A, B) == (A, B):
        print('this is fine, tuples use id I guess?')

    if [A, B] == [A, B]:
        print('this is also fine')

    # if A[0] == B[0]:
    #     print('this is no')

    # if (A[0], B[0]) == (A[0], B[0]):
    #     print('this is no, the id's aren't identical so it tries to check')

    # if A == B:
    #     print('this is no')

    print('So this is fine')
    for (x, y), it in groupby(A, key=tuple):
        for keyval in it:
            print('YAY', keyval)

    # print('But this barfs mysteriously')
    # for (x, y), it in groupby(A, key=lambda x: x):
    #     for keyval in it:
    #         print('Only one is printed, then exception', keyval)

    # print('The real pain is that this will not work')
    # for (x, y), it in groupby(zip(A, B), key=lambda x: x):
    #     for keyval in it:
    #         print('Only one is printed, then exception', keyval)

    # print('The real pain is that this will not work')
    # for (x, y), it in groupby(zip(A, B), key=tuple):
    #     for keyval in it:
    #         print('Only one is printed, then exception', keyval)


if __name__ == '__main__':
    fuck_my_face()