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Proposed Tail-Recursion for Python
def do_something():
exited_on_a = False
exited_on_b = False
exited_on_c = False
while 1:
...
if some_condition:
exited_on_a = True
break
...
if some_condition:
exited_on_b = True
break
...
if some_condition:
exited_on_b = True
break
...
if exited_on_a:
...
if exited_on_b:
...
if exited_on_c:
...
...
def do_something():
...
if some_condition:
recurse exit_a()
...
if some_condition:
recurse exit_b()
...
if some_condition:
recurse exit_c()
...
recurse do_something()
def exit_a():
...
recurse tail()
def exit_b():
...
recurse tail()
def exit_c():
recurse tail()
def tail():
...
from __future__ import tail_recursion
from framework import job
import framework.message as msg
# In this framework, all messages have a response. No data is stored in the
# response with the exception of the "init" message, which negotiates a job
# id used to associate subsequent results.
def new(init_message):
j = job(init_message)
j.send_and_wait(msg.reply(job.job_id))
allowed = job.authorize()
if not allowed:
recurse nack(job)
job.send_and_wait(msg.ack())
job.start() # This starts a generator stored at job.runner
recurse data(job)
def data(job):
try:
next = job.runner.next()
job.send(msg.data(next))
recurse data(job.runner.next())
except StopIteration:
recurse final(job)
except Exception,e:
recurse error(job,e):
def nack(job):
job.send_and_wait(msg.error("not-acknowledged"))
def error(job,e = None):
job.send(msg.error(e))
recurse job.abort()
def final(job):
job.wait_on_replies()
job.send(msg.final())
recurse job.done()
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