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June 29, 2018 04:49
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Faster geometric brownian motion
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function genS_jl(I) | |
s0 = 600.0 | |
r = 0.02 | |
sigma = 2.0 | |
T = 1.0 | |
M = 100 | |
dt = T/M | |
a = (r - 0.5*sigma^2)*dt | |
b = sigma*sqrt(dt) | |
paths = zeros(Float64, M, I) | |
for i in 1:I | |
paths[1, i] = st = s0 | |
for j in 2:M | |
st *= exp(a + b*randn()) | |
paths[j, i] = st | |
end | |
end | |
return paths | |
end | |
genS_jl(10) # Warm up JIT | |
@elapsed genS_jl(100000) # Outputs 0.538962298 |
Also note that if you just want to calculate the option price, you don't need to allocate any arrays at all because the option price only depends on the final value in each trajectory, and you can compute the average incrementally. You could write blazing fast straight scalar code that probably keeps everything in registers throughout.
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Thank you! I'm still new to julia so this helps a lot.