WordFrequency.rb

=begin
Define a method called frequency_table that will take a String as an argument and return a frequency table (using the Hash class), 
where each key is a word in the String and it's value is the number of times the word occurs in the sentence. 
The method should not be case sensitive. Assume that the input will always be a String. 
Return an empty Hash for an empty String.
=end

=begin
test:

describe "#frequency_table" do

  it "returns a frequency table based on the argument" do
    sentence = "This test is a TEST of the TesT"
    expected_outcome = {"this"=>1, "test"=>3, "is"=>1, "a"=>1, "of"=>1, "the"=>1}

    expect(frequency_table(sentence)).to eq(expected_outcome)
  end

  it "returns a frequency table based on the argument" do
    sentence = "I am legend AM am Am"
    expected_outcome = {"i"=>1, "am"=>4, "legend"=>1}

    expect(frequency_table(sentence)).to eq(expected_outcome)
  end

  it "returns an empty hash when called with no input" do
    expect(frequency_table('')).to eq({})
  end

end
=end


sentence = "This test is a TEST of the TesT"

def frequency_table(sentence)
  
  new_string = sentence.downcase.split(" ") 
  # = ["this", "test", "is", "a", "test", "of", "the", "test"]
  
  str = Hash.new
  # str = {}
  
  new_string.each do |key, value|
    
    value = 0
    
    
    
    # if key === key
    #   value += 1
    # end
    
    str[key] = value += 1
  end
  
  
  # => {"this"=>1, "test"=>1, "is"=>1, "a"=>1, "of"=>1, "the"=>1}
  
  str
  
  # => {"this"=>0, "test"=>7, "is"=>2, "a"=>3, "of"=>5, "the"=>6}
  
end

frequency_table(sentence)