Simulation to explain answer to pointers question

question.c

#include <stdio.h>

int main () {
	int c[3] = {4, 5, 6}; // an array is basically a pointer to the first element
	void *d = c; // cast int* to void*
	d += 1; // increment the void pointer
	printf("%08x\n", *((int *)d));
}

simulation.c

#include <stdio.h>
int main() {
  int c[3] = {4,5,6};
  // for the purposes of this simulation, only the last 3 digits of the memory address of each location are displayed
  
  printf("Lets print our array's memory locations, and their corresponding integer values:\n");
  int i = 0;
  while (i < 3){
    printf("value %02x is stored at address %3p\n", (unsigned)c[i], ((int)(c+i) & 0x00FFF) );
    i++;
  }// prints the contents at each memory location.
  
  int *d;
  d = c;
  void *e = c;
  
  printf("\n\nNow lets print the actual contents of memory:\n");
  for(i = 0; i < 12; i++){
    printf("value %02x is stored at address %02p\n", *(char *)(e+i), ((int)(e+i) & 0x00FFF) );
  }
  
  d += 1;
  e += 1;
  
  printf("\n\nTherefore:\n");
  printf("base address %02p holds (int) value %08x\n\n", ((int)c & 0x00FFF), *c);
  printf("integer incremeted address %02p holds integer value %08x \nbecause incrementing an integer pointer moved you forward by %ld bytes\n\n", ((int)d & 0x00FFF), *d, sizeof(*d));
  printf("void incremented address %02p holds integer value %08x \nbecause incrementing a void pointer moved you forward by %ld byte\n\n", ((int)e & 0x00FFF), *(int *)e, sizeof(*e));
}