Created
February 10, 2015 04:16
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/** | |
* Definition for binary tree | |
* public class TreeNode { | |
* int val; | |
* TreeNode left; | |
* TreeNode right; | |
* TreeNode(int x) { val = x; } | |
* } | |
*/ | |
public class Solution { | |
public TreeNode buildTree(int[] inorder, int[] postorder) { | |
int len = inorder.length; | |
return buildSubtree(inorder, 0, len - 1, postorder, 0, len - 1); | |
} | |
private TreeNode buildSubtree(int[] inorder, int lo1, int hi1, int[] postorder, int lo2, int hi2){ | |
if (lo1 > hi1) | |
return null; | |
TreeNode node = new TreeNode(postorder[hi2]); | |
int index = find(inorder,postorder[hi2], lo1, hi1); | |
int leftLen = index - lo1; | |
int rightLen = hi1 - index; | |
node.left = buildSubtree(inorder, lo1, index - 1, postorder, lo2, lo2 + leftLen - 1); | |
node.right = buildSubtree(inorder, index + 1, hi1, postorder, hi2 - rightLen, hi2 - 1); | |
return node; | |
} | |
private int find(int[] inorder, int target, int lo, int hi){ | |
for (int i = lo; i <= hi; i++){ | |
if (inorder[i] == target) | |
return i; | |
} | |
return -1; | |
} | |
} |
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