Last active
November 3, 2019 17:23
-
-
Save karpanGit/a676f06f34d9d568d70d72cb94f1ea00 to your computer and use it in GitHub Desktop.
pandas: ungrouping concatenated cells in a column of a pandas dataframe
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
# pandas ungroup operation | |
import pandas as pd | |
# create example dataframe df1.loc[3,'b'] contains duplicate values that will be dropped | |
df1 = pd.DataFrame({'a':[1,2,3,4],'b':['a;b;c','g','j;w','h;j;h']}) | |
print(df1) | |
''' | |
a b | |
0 1 a;b;c | |
1 2 g | |
2 3 j;w | |
3 4 h;j;h | |
''' | |
# ungroup the concatenated cells (operations listed separately for clarity) | |
res = df1['b'].str.split(';',expand=True).stack() | |
res.index = res.index.droplevel(level=1) | |
res.rename('b (new)', inplace=True) | |
res = res.groupby(level=0).unique().explode() | |
print(res) | |
''' | |
0 a | |
0 b | |
0 c | |
1 g | |
2 j | |
2 w | |
3 h | |
3 j | |
Name: b (new), dtype: object | |
''' | |
# join back to the dataframe | |
df1 = df1.join(res) | |
print(df1) | |
''' | |
a b b (new) | |
0 1 a;b;c a | |
0 1 a;b;c b | |
0 1 a;b;c c | |
1 2 g g | |
2 3 j;w j | |
2 3 j;w w | |
3 4 h;j;h h | |
3 4 h;j;h j | |
''' |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment