Calculate a number that is doubled over and over

double_number_calc.py

base = float(input("What is the base number? "))
double = int(input("How many times do you wish to double it? "))

for i in range(1, double+1):
    doubled_base = base * 2
    if doubled_base.is_integer():
        print(f"\n{doubled_base:.0f}\n\t\t(^ Number {i})")
    else:
        print(f"\n{doubled_base:.1f}\n\t\t(^ Number {i})")
    base = doubled_base