/* The stocks of a company are being surveyed to analyze the net profit of the company over a period of several months. For an analysis parameter k, a group of k consecutive months is said to be highly profitable if the values of the stock prices are strictly increasing for those months. Given the stock prices of the company for n months and the…

countHighlyProfitableMonths.js

function countHighlyProfitableMonths(stockPrices, k) {
    // write your code here
    let numOfProfitableMonths = 0
    let stockPriceLen = stockPrices.length
    let profitableMonthsArr = [stockPrices[0]]

    for (let i = 1; i < stockPriceLen; i += 1) {
        const currStockPrice = stockPrices[i]
        // checking current stock price against the profitable array
        if (currStockPrice > profitableMonthsArr[profitableMonthsArr.length - 1]) {
            if (profitableMonthsArr.length === k) {
              // drop the first element
              profitableMonthsArr.shift()
            }
            profitableMonthsArr.push(currStockPrice)
        } else {
            // if we need to start the array over
            profitableMonthsArr = [currStockPrice]
        }
      
        if (profitableMonthsArr.length === k) {
            numOfProfitableMonths += 1
        }
    }
  
    return numOfProfitableMonths
}


let stockPrices = [5, 3, 5, 7, 8]
let k = 3
// let res = countHighlyProfitableMonths(stockPrices, k)
console.log(countHighlyProfitableMonths(stockPrices, k) === 2)
console.log(countHighlyProfitableMonths([1,2,3,4,5,6,7,8,9], 3) === 7)
console.log(countHighlyProfitableMonths([1,2,3,4,5,6,7,8,9], 6) === 4)
console.log(countHighlyProfitableMonths([1,2,8,45,6,37,8,9], 6) === 0)
console.log(countHighlyProfitableMonths([1,2,8,45,6,37,8,9], 3) === 2)


// console.log(res)


//countHighlyProfitableMonths([1,2,3,4,5,6,7,8,9], 3) //7
//countHighlyProfitableMonths([1,2,3,4,5,6,7,8,9], 6) //4
//countHighlyProfitableMonths([1,2,8,45,6,37,8,9], 6) //0
//countHighlyProfitableMonths([1,2,8,45,6,37,8,9], 3) //2