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@keisukeYamagishi
Created January 29, 2017 04:36
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<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<script src="./sameNumber.js"></script>
</body>
</html>
/**
* Created by shichimi on 2016/07/01.
*/
/*
*
* (*_*).oO .. create random array hahaha!
*
* */
var create = function createing(number) {
var array = [];
for(var i=0;i<number;i++){
var rand = Math.floor(Math.random()*100);
array[i] = rand;
}
return array;
}
/*
*
* (*_*).oO .. wirte page resule
*
* */
var logsort = function logs (ary) {
for(var re=0;re<ary.length;re++){
document.write(ary[re] + ", ");
}
}
/*
*
* ($_$).oO ... search same Number
*
* */
var sameNumber = function same(A,B) {
var answer =0;
document.write("<br>start<br>");
for(var sa = 0; sa<A.length;sa++){
for(var ba = 0; ba < B.length; ba++){
if(A[sa]==B[ba]) {
document.write("<br> A=> " + A[sa] + " B=> " + B[ba]);
answer++;
}
}
}
document.write("<br>" + "<h1> answer => " + answer);
}
var a=create(30);
document.write("<br>");
var b=create(20);
document.write("A+>");
logsort(a);
document.write("<br>" + "B=>");
logsort(b);
sameNumber(a,b);
@keisukeYamagishi
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A配列のXとB配列のXが同じ数字だった時、1カウントする。
A配列とB配列を全て走査し、同じ数字がいくつあるか調べるアルゴリズム

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