Go言語でパス情報から拡張子なしのファイル名を取り出したい ref: http://qiita.com/KemoKemo/items/d135ddc93e6f87008521

file1.txt

$ go run GetFileNameWithoutExt.go
path\to\file.name.hoge.name -> file.name.hoge
path\to\file.name -> file
path\to\file -> file

GetFileNameWithoutExt.go

package main

import (
    "fmt"
    "path/filepath"
)

func main() {
    paths := []string{
        filepath.Join("path", "to", "file.name.hoge.name"),
        filepath.Join("path", "to", "file.name"),
        filepath.Join("path", "to", "file"),
    }

    for _, path := range paths {
        filename := getFileNameWithoutExt(path)
        fmt.Printf("%s -> %s\n", path, filename)
    }
}

func getFileNameWithoutExt(path string) string {
    // Fixed with a nice method given by mattn-san
    return filepath.Base(path[:len(path)-len(filepath.Ext(path))])
}

mattnさんにコメントでいただいた処理で修正しました！