ZIP by GO (Copied from [StackOverFlow](http://stackoverflow.com/questions/20357223/easy-way-to-unzip-file-with-golang))

zip.go

package main

import (
	"archive/zip"
	"fmt"
	"io"
	"log"
	"os"
	"path/filepath"
)

func main() {
	fmt.Println("Hogehoge")
	err := Unzip("./HOGE.zip", ".")
	if err != nil {
		log.Fatal(err)
	}
}

func Unzip(src, dest string) error {
	r, err := zip.OpenReader(src)
	if err != nil {
		return err
	}
	defer func() {
		if err := r.Close(); err != nil {
			panic(err)
		}
	}()

	os.MkdirAll(dest, 0755)

	// Closure to address file descritpors issue with all the defered.close method
	extractAndWriteFile := func(f *zip.File) error {
		rc, err := f.Open()
		if err != nil {
			return err
		}
		defer func() {
			if err := rc.Close(); err != nil {
				panic(err)
			}
		}()

		path := filepath.Join(dest, f.Name)

		if f.FileInfo().IsDir() {
			os.MkdirAll(path, f.Mode())
		} else {
			f, err := os.OpenFile(path, os.O_WRONLY|os.O_CREATE|os.O_TRUNC, f.Mode())
			if err != nil {
				return err
			}
			defer func() {
				if err := f.Close(); err != nil {
					panic(err)
				}
			}()

			_, err = io.Copy(f, rc)
			if err != nil {
				return err
			}
		}
		return nil
	}

	for _, f := range r.File {
		err := extractAndWriteFile(f)
		if err != nil {
			return err
		}
	}
	return nil
}

Copied from this StackOverFlow for Go Practice as well as future reference