Skip to content

Instantly share code, notes, and snippets.

@kennydude

kennydude/failproxy.py

Created May 30, 2011 19:10
Show Gist options
  • Star 0 You must be signed in to star a gist
  • Fork 0 You must be signed in to fork a gist
  • Save kennydude/999337 to your computer and use it in GitHub Desktop.
Save kennydude/999337 to your computer and use it in GitHub Desktop.
Download ZIP
FailProxy
Raw
failproxy.py
'''
FailProxy
created by @kennydude
You need a failproxy.txt in the same directory as this script.
Then launch, configure your browser to connect here.
Now put something in failproxy.txt, save and reload.
Whoops! You just cut off access, remove contents of that file to restore access
'''
FAIL_PAGE = '''
<html>
<head><title>FailProxy</title></head>
<body><h1>FailProxy</h1><p>The FailProxy has been told to stop this!</p>
<p>Re-enable access by editing failproxy.txt to equal blank</p>
</body>
</html>
'''
print "FAILSERVER STARTING"
import SimpleHTTPServer
import SocketServer, urllib
PORT = 8001
class FailHandler( SimpleHTTPServer.SimpleHTTPRequestHandler ):
def req(self):
f_lock = open("failproxy.txt", "r")
f = f_lock.read()
f_lock.close()
if(f == ""):
# proxy page
self.copyfile(urllib.urlopen(self.path), self.wfile)
else:
self.send_response(503, "FAILSERVER")
self.send_header("Content-type", "text/html")
self.end_headers()
self.wfile.write(FAIL_PAGE)
def do_GET(self):
self.req()
def do_POST(self):
self.req()
Handler = FailHandler
httpd = SocketServer.ForkingTCPServer(("", PORT), Handler)
print "serving at port", PORT
try:
httpd.serve_forever()
except KeyboardInterrupt:
print "finish"
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment