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List all files in a directory in Node.js recursively in a synchronous fashion
// List all files in a directory in Node.js recursively in a synchronous fashion
var walkSync = function(dir, filelist) {
var fs = fs || require('fs'),
files = fs.readdirSync(dir);
filelist = filelist || [];
files.forEach(function(file) {
if (fs.statSync(dir + file).isDirectory()) {
filelist = walkSync(dir + file + '/', filelist);
}
else {
filelist.push(file);
}
});
return filelist;
};
@SakiiR
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SakiiR commented Jul 16, 2020

mmh Carefull with globby ;)

Here is my way (with typescript):

import fs from "fs/promises";
import path from "path";

export default async function walk(directory: string) {
  let fileList: string[] = [];

  const files = await fs.readdir(directory);
  for (const file of files) {
    const p = path.join(directory, file);
    if ((await fs.stat(p)).isDirectory()) {
      fileList = [...fileList, ...(await walk(p))];
    } else {
      fileList.push(p);
    }
  }

  return fileList;
}

@ariassd
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ariassd commented Dec 8, 2020

Alternative solution in Just two lines, Just for fun and learning

const path = ''; // 👈 path to your location
const list = require("child_process").execSync(`cd ${path} && ls -R`).toString().split(`\n`);

⚠️ IMPORTANT
Be careful, this solution use a bash script and it works fine in MACOS, for windows or linux could be different

@kiuKisas
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kiuKisas commented Feb 18, 2021

What I use is based on @vidul-nikolaev-petrov version, with a callback argument to do something with files:

const walkSync = (dir, callback) =>  fs.lstatSync(dir).isDirectory()
        ? fs.readdirSync(dir).map(f => walkSync(path.join(dir, f), callback))
        : callback(dir);

// Note: call to flat at the end to have one array with every paths
const svgs = walkSync(path, fileToBase64).flat()

@SakiiR
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SakiiR commented Feb 18, 2021

Alternative solution in Just two lines, Just for fun and learning

const path = ''; // 👈 path to your location
const list = require("child_process").execSync(`cd ${path} && ls -R`).toString().split(`\n`);

⚠️ IMPORTANT
Be careful, this solution use a bash script and it works fine in MACOS, for windows or linux could be different

Please, never do that

@Aleksandar1932
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Aleksandar1932 commented Jan 28, 2022

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