khannasarthak

print ("Hello World")

khannasarthak

import pandas as pd
pd.options.display.float_format = '{:.2f}'.format # Setting float precision   

# Reading CSV's and parsing dates
sales = pd.read_csv('take_home_sales.csv', sep='|',index_col=False,parse_dates=['timestamp'])
storeStatus = pd.read_csv('take_home_store_status.csv', sep='|',index_col=False)
stores = pd.read_csv('take_home_stores.csv', sep='|',index_col=False)


def cleanCSV():

khannasarthak

Coding Interview University

I originally created this as a short to-do list of study topics for becoming a software engineer, but it grew to the large list you see today. After going through this study plan, I got hired as a Software Development Engineer at Amazon! You probably won't have to study as much as I did. Anyway, everything you need is here.

The items listed here will prepare you well for in an interview at just about any software company, including the giants: Amazon, Facebook, Google or Microsoft. >

khannasarthak

package com.healthmonitor.khann.healthmonitor;

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.content.Intent;
import android.widget.EditText;
import com.jjoe64.graphview.GraphView;
import com.jjoe64.graphview.series.DataPoint;
import com.jjoe64.graphview.series.LineGraphSeries;

khannasarthak

#!/usr/bin/python3
import requests
import json
from urllib.request import urlopen
from gi.repository import Notify
import time


rbtc = requests.get(url='https://blockchain.info/ticker')
objbtc = rbtc.json()

khannasarthak

def dist(a,b):
	return ((a[0]-b[0])**2 + (a[1] -b[1])**2)

t = int(input())
while (t!=0):
	t -= 1
	a = list(map(int,(input().split())))
	# do not use split(' '), Gives rise to EOF or literal errors 
	k = [a[i:i+2] for i in range(0, len(a), 2)]
	p1 = k[0]

khannasarthak

def dist(a,b):
	return ((a[0]-b[0])**2 + (a[1] -b[1])**2)

t = int(input())
while (t!=0):
	a = list(map(int,(input().split(' '))))
	k = [a[i:i+2] for i in range(0, len(a), 2)]
	p1 = k[0]
	p2 = k[1]
	p3 = k[2]