Created
July 27, 2018 16:52
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Задача о сравнении подходов
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import random | |
from collections import defaultdict | |
from functools import reduce | |
from timeit import timeit | |
from itertools import groupby | |
from operator import itemgetter | |
from statistics import mean | |
AMAX = 65 | |
l = [{'age': random.randint(18, AMAX), 'rate': random.randint(1, 1000)} | |
for x in range(100000)] | |
# ======================== | |
def max_for(l): | |
totals = [0 for i in range(AMAX + 1)] | |
counters = [0 for i in range(AMAX + 1)] | |
for p in l: | |
totals[p['age']] += p['rate'] | |
counters[p['age']] += 1 | |
averages = [] | |
for i, v in enumerate(counters): | |
if counters[i] > 0: | |
averages.append(totals[i] / counters[i]) | |
return max(averages) | |
# ======================== | |
# ======================== | |
def max_map(l): | |
def fn(a, b): | |
a[b['age']].append(b['rate']) | |
return a | |
return max( | |
map( | |
lambda x: sum(x) / len(x), | |
reduce(fn, [defaultdict(list)] + l).values() | |
) | |
) | |
# ======================== | |
def max_fun(l): | |
return max([mean(i['rate'] for i in g) | |
for k, g in groupby(l, key=itemgetter('age'))]) | |
t1 = timeit('max_for(l)', 'from __main__ import max_for, l', number=1) | |
t2 = timeit('max_map(l)', 'from __main__ import max_map, l', number=1) | |
t3 = timeit('max_fun(l)', 'from __main__ import max_fun, l', number=1) | |
print(t1) | |
print(t2) | |
print(t3) |
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The results between
max_fun(l)
andmax_for(l) | max_map(l)
are not equal if we takel
from code above. But everything is ok when test list is small. So, there is some logical bug inmax_fun
(or vice versa inmax_for | max_map
?).l = [{'age': random.randint(18, 65), 'rate': random.randint(1, 1000)} for x in range(100000)]
print(max_for(l)) #>> 512.7681692732291
print(max_map(l)) #>> 512.7681692732291
print(max_fun(l)) #>> 1000
test = [{'age': 18, 'rate': 30}, {'age': 18, 'rate': 15}, {'age': 50, 'rate': 35}]
print(max_for(test)) #>> 35.0
print(max_map(test)) #>> 35.0
print(max_fun(test)) #>> 35