bash argv forwarding: $* vs $@ vs "$*" vs "$@" -- use "$@"

bash-argv-forwarding

#!/usr/bin/env bash

fn() {
	base="$1"
	shift
	printf "$base with \$*\n"
	for i in  $* ; do printf "  $i\n"; done;
	printf "$base with \$@\n"
	for i in  $@ ; do printf "  $i\n"; done;
	printf "$base with \"\$*\"\n"
	for i in "$*"; do printf "  $i\n"; done;
	printf "$base with \"\$@\"\n"
	for i in "$@"; do printf "  $i\n"; done;
	printf "\n"
}

fn   '$*'    $*
fn   '$@'    $@
fn '\"$*\"' "$*"
fn '\"$@\"' "$@"

# singular
#for i in  $* ; do echo $i; done; echo ""
#for i in  $@ ; do echo $i; done; echo ""
#for i in "$*"; do echo $i; done; echo ""
#for i in "$@"; do echo $i; done; echo ""

result.txt

$ ./bash-argv-forwarding a "b c"

$* with $*
  a
  b
  c
$* with $@
  a
  b
  c
$* with "$*"
  a b c
$* with "$@"
  a
  b
  c

$@ with $*
  a
  b
  c
$@ with $@
  a
  b
  c
$@ with "$*"
  a b c
$@ with "$@"
  a
  b
  c

"$*" with $*
  a
  b
  c
"$*" with $@
  a
  b
  c
"$*" with "$*"
  a b c
"$*" with "$@"
  a b c

"$@" with $*
  a
  b
  c
"$@" with $@
  a
  b
  c
"$@" with "$*"
  a b c
"$@" with "$@"
  a
  b c