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March 5, 2013 09:06
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Python验证用户输入IP的合法性,有什么好方法吗?
如:<input type="text" name="ip" id="ip" /> 在text里表单输入的字符串
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#!/usr/bin/python | |
#-*- coding: utf-8 -*- | |
''' | |
http://segmentfault.com/q/1010000000174213 | |
Python验证用户输入IP的合法性,有什么好方法吗? | |
如:<input type="text" name="ip" id="ip" /> 在text里表单输入的字符串 | |
''' | |
########################################################################### | |
# 1. 通过正则表达式判断 | |
import re | |
def ipFormatChk(ip_str): | |
pattern = r"\b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b" | |
if re.match(pattern, ip_str): | |
return True | |
else: | |
return False | |
########################################################################### | |
# 2. 根据ip地址的特性,使用Python内置函数来实现 | |
def ip_check(ip): | |
q = ip.split('.') | |
return len(q) == 4 and len(filter(lambda x: x >= 0 and x <= 255, \ | |
map(int, filter(lambda x: x.isdigit(), q)))) == 4 | |
# 上述两种方法仅对ipv4有效 | |
########################################################################### | |
# 3. 使用第三方库实现 | |
''' | |
从 Python 3.3 开始标准库中提供了ipaddress模块(http://docs.python.org/dev/library/ipaddress.html#module-ipaddress),之前的Python版本则可以通过PyPi安装相应的版本(https://pypi.python.org/pypi/ipaddress/1.0.3)。 | |
''' |
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使用内置isdigit()函数校验时,
在Python3中,filter和map等方法返回的并不是list,而是对应的filter和map对象,需要用list()将对象转换成list才行