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August 20, 2012 04:59
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Project Euler 問題29 その2
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| #!/usr/local/bin/octave -q | |
| % parse arguments | |
| _argv = argv(); | |
| amin = str2num(char(_argv(1))); | |
| amax = str2num(char(_argv(2))); | |
| bmin = str2num(char(_argv(3))); | |
| bmax = str2num(char(_argv(4))); | |
| % calc | |
| v = [amin:1:amax]'.^[amin:1:amax]; | |
| v = sort(unique(v)); | |
| ans = length(v); | |
| % disp | |
| printf("(%d<=a<=%d, %d<=b<=%d) Ans: %d\n", amin, amax, bmin, bmax, ans); | |
| % <Answer> | |
| % (2<=a<=100, 2<=b<=100) Ans: 9183 |
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すんなりできた。