Created
January 10, 2016 15:02
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#include <iostream> | |
#include <cstdio> | |
#include <cmath> | |
#include <vector> | |
#include <algorithm> | |
#include <string> | |
#include <set> | |
using namespace std; | |
typedef long long int ll; | |
#define rep(i,n) for(int i=0; i<(int)(n);i++) | |
ll n, temp; | |
int main(){ | |
cin >> n; | |
vector<int> d[n+1]; | |
temp = 1; | |
for(int i = 1; i <= n;i++){ | |
temp *= i; | |
ll a = temp; | |
bool er = false; | |
for(int j=0; a>=0;j++, a/=10){ | |
int key = a%10; | |
if(j == 0 && key == 0) er = true; | |
if(key!=0) er = false; | |
if(er==false)d[i].push_back(key); | |
if(d[i].size()==9) break; | |
} | |
temp = 0; | |
for(int j=1,k=0; k < d[i].size(); j*=10, k++){ | |
temp += j*d[i][k]; | |
} | |
} | |
bool p = false; | |
int k = d[n].size()-1; | |
for(int i = k; i>=0;i--){ | |
if(i==k && d[n][i] ==0) p = true; | |
if(d[n][i] != 0) p = false; | |
if(p==false)cout << d[n][i]; | |
} | |
return 0; | |
} |
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