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@knotman90
Last active September 30, 2018 19:15
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#include <algorithm>
#include <array>
#include <cmath>
#include <iostream>
#include <iterator>
#include <limits>
#include <numeric>
#include <unordered_map>
#include <vector>
using namespace std;
/*
- input: numero intero ( 1 <= n <= 500)
1. convertilo in binario
2. n interazioni `n` <= 30
- carattere 0 diventa 01
- carattere 1 diventa 10
qual è il valore del carattere dopo `n` iterazioni
*/
/*
k=23
n=3
10011
1.
1001011010
2.
0 -> 01 -> 0110 -> 01101001 ->
1 -> 10 -> 1001 -> 10010110
*/
bool solve(const vector<bool>& S, long k, int n, const int d) {
if (n == 0) {
return S[d];
}
if (k >= (1 << (n - 1))) { // second
return !solve(S, k - (1 << (n - 1)), n - 1, d);
} else { // first
return solve(S, k, n - 1, d);
}
}
vector<bool> bruteforce(vector<bool> S, int n){
if(n<=0)
return S;
vector<bool> S1;
S1.reserve(S.size()*2);
for (int i = 0; i < S.size(); ++i)
{
if(S[i]){
S1.push_back(true);
S1.push_back(false);
}else{
S1.push_back(false);
S1.push_back(true);
}
}
return bruteforce(S1 ,n-1);
}
int main() {
int k = 20;
int n = 3;
vector<bool> S = {1, 0, 0, 0, 1, 1, 0, 1};
vector<bool> ans = bruteforce(S , n);
cout<<"referece:";
for(auto a : ans){
cout<<a;
}
cout<<endl;
cout<<"answer: ";
for (int i = 0; i < S.size()*(1<<n); ++i) {
k = i;
long d = k / (1 << n);
long kk = k % (1 << n);
const auto ansi = solve(S, kk, n, d);
if(ansi != ans[i])
cout<<"error at position"<<i<<endl;
cout << ansi << "";
}
cout<<endl;
return 0;
}
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