Created
February 5, 2019 12:14
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class Solution { | |
private class DisjointSet { | |
private int[] root, size; | |
private DisjointSet(int n) { | |
root = new int[n]; | |
size = new int[n]; | |
for (int i = 0; i < n; i++) { | |
root[i] = i; | |
size[i] = 1; | |
} | |
} | |
private int root(int x) { | |
return x == root[x] ? x : (root[x] = root(root[x])); | |
} | |
private void join(int a, int b) { | |
int x = root(a), y = root(b); | |
if (x != y) { | |
if (size[x] < size[y]) y = x ^ y ^ (x = y); | |
root[y] = x; | |
size[x] += size[y]; | |
} | |
} | |
} | |
public boolean areSentencesSimilarTwo(String[] words1, String[] words2, String[][] pairs) { | |
Map<String, Integer> map = new HashMap<>(); | |
int idx = 0; | |
for (String[] pair : pairs) { | |
for (int i = 0; i < 2; i++) { | |
if (!map.containsKey(pair[i])) { | |
map.put(pair[i], idx++); | |
} | |
} | |
} | |
DisjointSet dsu = new DisjointSet(4005); | |
for (String[] pair : pairs) { | |
dsu.join(map.get(pair[0]), map.get(pair[1])); | |
} | |
boolean similar = words1.length == words2.length; | |
if (similar) { | |
int n = words1.length; | |
for (int i = 0; i < n; i++) { | |
int x = map.get(words1[i]), y = map.get(words2[i]); | |
similar &= dsu.root(x) == dsu.root(y); | |
} | |
} | |
return similar; | |
} | |
} |
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