FizzBuzz one-liner in Python 3

fizzbuzz.py

# Using a lambda function
print(list(map(lambda i: "Fizz"*(i%3==0)+"Buzz"*(i%5==0) or str(i), range(1,101))))

# Using a for loop
for i in range(1, 101): print("Fizz"*(i%3==0)+"Buzz"*(i%5==0) or str(i))

@ijknabla some next level memory management 👌😂👏
would even be 2 bytes since you also changed it for the divisible by 5 or was it already 1 byte for both?

@JonathanDagan
YES

• i%3==0 → i%3<1 (-1 bytes)
• i%5==0 → i%5<1 (-1 bytes)
  total 2 bytes

@ijknabla

💯

Similar in length, but using a different technique, and I'm using input and count (itertools), so it goes forever but is user controlled:

[input("fizz"[i%3*4:] + "buzz"[i%5*4:] or i) for i in count(1)]

I guess count shaves off a few more characters as well.