Gulpfile im using with Gulp 4 with error notifying and plumber

gulpfile.coffee

gulp       = require 'gulp'

babel      = require 'gulp-babel'
sourcemaps = require 'gulp-sourcemaps'
concat     = require 'gulp-concat'
uglify     = require 'gulp-uglify'

sass       = require 'gulp-sass'
minCss     = require 'gulp-minify-css'
prefix     = require 'gulp-autoprefixer'

plumber    = require 'gulp-plumber'
gutil      = require 'gulp-util'
notify     = require 'gulp-notify'

sync       = require('browser-sync').create()

# Options
options =
  SASS_SRC:   './assets/style/style.scss'
  SASS_FILES: './assets/style/**/*.scss'
  SASS_DEST:  './'

  JS_SRC:     './assets/js/**/*.js'
  JS_DEST:    './assets/'
  JS_BUNDLE:  'bundle.min.js'

gulp.task 'style', (done) ->
  gulp.src options.SASS_SRC
    .pipe plumber()
    .pipe sourcemaps.init()
    .pipe sass(
      outputStyle: 'expanded'
      errLogToConsole: false,
    ).on('error', notify.onError())
    .pipe prefix browsers: ["last 2 versions", "> 5%"]
    .pipe minCss keepSpecialComments: "*"
    .pipe sourcemaps.write '.'
    .pipe gulp.dest options.SASS_DEST
    .pipe sync.stream()
    .pipe notify message: 'Building CSS successful', onLast: true

  done()

gulp.task 'scripts', (done) ->
  gulp.src options.JS_SRC
    .pipe plumber()
    .pipe sourcemaps.init()
    .pipe babel()
      .on 'error', notify.onError()
    .pipe concat options.JS_BUNDLE
    .pipe sourcemaps.write '.'
    .pipe gulp.dest options.JS_DEST
    .pipe sync.stream()
    .pipe notify message: 'Building JS successful', onLast: true

  done()

gulp.task 'watch', ->
  sync.init proxy: 'domain.local'

  # Watch for sass changes
  gulp.watch options.SASS_FILES, gulp.parallel 'style'
    .on 'change', sync.reload

  # Watch for js changes
  gulp.watch options.JS_SRC, gulp.parallel 'scripts'
    .on 'change', sync.reload

gulp.task 'build', gulp.parallel 'style', 'scripts', (done) ->
	done()

gulp.task 'default', gulp.series 'build', 'watch', (done) ->
  done()