D7-PHP-field rendering

d7-php-field-rendering.php

Output field as is in drupal ui:
$output = field_view_field('node', $node, 'field_name');


Just want a single value, and none of the field markup:
$node = node_load($nid);
$field = field_get_items('node', $node, 'field_name');
$output = field_view_value('node', $node, 'field_name', $field[$delta]);


Display the field based on drupals specific display settings:
$field = field_get_items('node', $node, 'field_name');
$instance = field_read_instance('node', 'field_name', 'content_type_machine_name');
$field = field_view_value('node', $node, 'field_name', $field[$delta], $instance['display']['default']);


Passing in some formatter options:
This would work the same for both field_view_value() and field_view_field().
<?php
$node = node_load($nid);
$image = field_get_items('node', $node, 'field_image');
$output = field_view_value('node', $node, 'field_image', $image[0], array(
  'type' => 'image',
  'settings' => array(
    'image_style' => 'thumbnail',
    'image_link' => 'content',
  ),
)); 
?>


Output Of The Field with access checks:

//field permissions from any module
<?php if (!empty($image) && field_access('view', field_info_field('field_image'), 'node', $node)) : ?>
<div class="field-output">
  <?php print render($output); ?>
</div>
<?php endif; ?>