Created
August 31, 2020 12:06
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class Solution: | |
# @param A : tuple of list of integers | |
# @return a list of integers | |
def spiralOrder(self, A): | |
n,m = len(A),len(A[0]) | |
l,r,t,d = 0,m-1,0,n-1 | |
ans = [] | |
direction = 0 | |
while l<= r and t <= d : | |
if direction == 0 : | |
for i in range(l,r+1): | |
ans.append(A[t][i]) | |
t += 1 | |
elif direction == 1 : | |
for i in range(t,d+1): | |
ans.append(A[i][r]) | |
r -= 1 | |
elif direction == 2 : | |
for i in range(r,l-1,-1): | |
ans.append(A[d][i]) | |
d -= 1 | |
elif direction == 3 : | |
for i in range(d,t-1,-1): | |
ans.append(A[i][l]) | |
l += 1 | |
direction = (direction+1)%4 | |
return ans |
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