Given the head of a singly linked list, return true if it is a palindrome

palinedrome_linked-list.py

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def isPalindrome(self, head: ListNode) -> bool:
        numbers = []
        sentinel = head
        while sentinel:
            numbers.append(sentinel.val)
            sentinel = sentinel.next
        return numbers == numbers[::-1]