Project Euler - Problem 6 - Sum square difference

p6_projecteuler.cpp

/* 
Project_6.cpp : Sum square difference

The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + ... + 10^2 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)^2 = 55^2 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers 
and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of 
the first one hundred natural numbers and the square of the sum.
*/

#include <iostream>
using namespace std;

int main()
{
	int sum1 = 0, sum2 = 0;

	for (int i = 1; i < 101; i++)
	{
		sum1 += i * i;
	}
	for (int j = 0; j < 101; j++)
	{
		sum2 += j;
	}

	cout << "Result is:\n" << sum2 * sum2 << " - " << sum1 << " = " << 
		(sum2*sum2) - sum1 << endl;

    return 0;
}