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Leetcode: 623. Add One Row to Tree.
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// Leetcode: 623. Add One Row to Tree. | |
// https://leetcode.com/problems/add-one-row-to-tree/ | |
package main | |
/** | |
* Definition for a binary tree node. | |
* type TreeNode struct { | |
* Val int | |
* Left *TreeNode | |
* Right *TreeNode | |
* } | |
*/ | |
func addOneRow(root *TreeNode, val int, depth int) *TreeNode { | |
if 1 == depth { | |
return &TreeNode{val, root, nil} | |
} | |
totalDepth := getDepth(root, 0) | |
var q1 []*TreeNode | |
var q2 []*TreeNode | |
q1 = make([]*TreeNode, 0) | |
q1 = append(q1, root) | |
for i := 1; 0 != len(q1); i += 1 { | |
q2 = make([]*TreeNode, 0) | |
if i+1 == depth { | |
for _, v := range q1 { | |
if i+1 > totalDepth { | |
tmpL := &TreeNode{val, nil, nil} | |
tmpR := &TreeNode{val, nil, nil} | |
v.Left = tmpL | |
v.Right = tmpR | |
} else { | |
if nil != v.Left { | |
tmp := &TreeNode{val, nil, nil} | |
tmp.Left = v.Left | |
v.Left = tmp | |
q2 = append(q2, tmp) | |
} | |
if nil != v.Right { | |
tmp := &TreeNode{val, nil, nil} | |
tmp.Right = v.Right | |
v.Right = tmp // <==== Here. | |
q2 = append(q2, tmp) | |
} | |
} | |
} | |
} else { | |
for _, v := range q1 { | |
if nil != v.Left { | |
q2 = append(q2, v.Left) | |
} | |
if nil != v.Right { | |
q2 = append(q2, v.Right) | |
} | |
} | |
} | |
q1 = q2 | |
q2 = nil | |
} | |
return root | |
} | |
func getDepth(x *TreeNode, depth int) int { | |
if nil == x { | |
return depth | |
} | |
a := getDepth(x.Left, depth+1) | |
b := getDepth(x.Right, depth+1) | |
if a > b { | |
return a | |
} else { | |
return b | |
} | |
} |
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// Leetcode: 623. Add One Row to Tree. | |
// https://leetcode.com/problems/add-one-row-to-tree/ | |
// = = = = = = = = = = = = = = | |
// Accepted. | |
// Thanks God, Jesus Christ! | |
// = = = = = = = = = = = = = = | |
// Runtime: 5 ms, faster than 55.17% of Go online submissions for Add One Row | |
// to Tree. | |
// Memory Usage: 5.8 MB, less than 100.00% of Go online submissions for Add | |
// One Row to Tree. | |
// 2024.04.16 Dayily Challange, copied from 2022.10.06. | |
/** | |
* Definition for a binary tree node. | |
* type TreeNode struct { | |
* Val int | |
* Left *TreeNode | |
* Right *TreeNode | |
* } | |
*/ | |
func addOneRow(root *TreeNode, val int, depth int) *TreeNode { | |
if 1 == depth { | |
el := &TreeNode{Val: val, Left: root, Right: nil} | |
return el | |
} | |
root.Left = rec(root.Left, val, depth-1, 'l') | |
root.Right = rec(root.Right, val, depth-1,'r') | |
return root | |
} | |
func rec(x *TreeNode, val int, d int, side int) *TreeNode{ | |
if d < 1 { return x} | |
if 1 == d { | |
el := &TreeNode{Val: val, Left: nil, Right: nil} | |
if 'l' == side { | |
el.Left = x | |
} | |
if 'r' == side{ | |
el.Right = x | |
} | |
return el | |
} | |
if nil == x { return x} | |
x.Left = rec(x.Left, val, d-1, 'l') | |
x.Right = rec(x.Right, val, d-1, 'r') | |
return x | |
} |
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